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Agent skill · Audited from source

classical-cipher-analysis

skill · yaklang/hack-skillsMIT licenceAudited 31 Oct 2026 · source a6bc8e8fefb6

★ 2,599pushed 48 days ago
✓SAFEGrade B · 89/100 · 31 Oct 2026 · a6bc8e8
2,599repo stars · whole yaklang/hack-skills

Is it safe? Yes — SAFE, grade B (89/100). We read this skill's source at commit a6bc8e8fefb6 and found no filesystem, network or shell access and no hard-coded secrets. What it does: Classical cipher analysis playbook. Use when encountering substitution ciphers, Vigenere, transposition, XOR, or encoded text in CTF challenges that requires frequency analysis, Kasiski examination, or known-plaintext…

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Cite this page

ModelsAtlas. “classical-cipher-analysis (yaklang/hack-skills)”. Retrieved 31 Oct 2026. https://modelsatlas.com/skills/yaklang/classical-cipher-analysis

Trust audit

Audit 0.4.1 · source read 31 Oct 2026

Trust score89/100✓SAFE B
0 critical0 high0 medium0 low0 info

SAFE means nothing in the source contradicts what the skill says it does. Grade B is shared by 16,667 of 17,602 audited skills.

What the source does

  • FilesystemNone observedNo reads or writes in the source
  • NetworkNone observedNo outbound calls in the source
  • ShellNone observedNo commands run in the source
  • DependenciesPinnedNothing floats
  • SecretsNone foundNo keys in source

Five audit layers

LayerWhat we checkResultFindings
L0 ProvenanceRepo owner, licence, archive status, activityPASS0
L1 Static sourceSecrets, path traversal, supply chain, hidden codeNA0
L2 InstructionsPrompt injection, authority framing, hidden directivesPASS0
L3 InventoryThe files and declarations match the sourcePASS0
L4 SandboxRun in isolation and watch behaviourSKIPPED why0

Gates applied: no behavioural pass.

Findings (0)

No findings at any severity. We re-audit when the source changes.

Audit 0.4.1 · source sha a6bc8e8fefb6 · 31 Oct 2026Report an issue or request a re-scan

Provenance

Who published it, and what the verdict is pinned to

  • Publisheryaklang GitHub organizationOwner of the repository this skill is read from
  • Source folderyaklang/hack-skills/skills/classical-cipher-analysisThe exact folder we audited
  • LicenceMITAs the repository states it
  • Commit pinned for this verdicta6bc8e8fefb6A new audit runs when the source changes
  • Repository statusNot archivedLast push 48 days ago
  • Sandboxed runNot runSkills are read, not executed; layer L4 is skipped

What it tells the agent

Full source on GitHub ↗

Its description: Classical cipher analysis playbook. Use when encountering substitution ciphers, Vigenere, transposition, XOR, or encoded text in CTF challenges that requires frequency analysis, Kasiski examination, or known-plaintext…

---
name: classical-cipher-analysis
description: >-
  Classical cipher analysis playbook. Use when encountering substitution
  ciphers, Vigenere, transposition, XOR, or encoded text in CTF challenges
  that requires frequency analysis, Kasiski examination, or known-plaintext
  cryptanalysis.
---

# SKILL: Classical Cipher Analysis — Expert Cryptanalysis Playbook

> **AI LOAD INSTRUCTION**: Expert classical cipher identification and breaking techniques for CTF. Covers cipher identification methodology (frequency analysis, IC, Kasiski), monoalphabetic substitution, Caesar/ROT, Vigenere, Enigma, affine, Hill, transposition ciphers, Bacon/Polybius/Playfair, and XOR ciphers. Base models often skip the identification step and jump to the wrong cipher type, or fail to recognize encoded (base64/hex) ciphertext that needs decoding before analysis.

## 0. RELATED ROUTING

- [symmetric-cipher-attacks](../symmetric-cipher-attacks/SKILL.md) when dealing with modern symmetric ciphers (AES/DES) rather than classical
- [hash-attack-techniques](../hash-attack-techniques/SKILL.md) when the challenge involves hash-based constructions
- [lattice-crypto-attacks](../lattice-crypto-attacks/SKILL.md) when knapsack-based ciphers are encountered

### Quick identification guide

| Observation | Likely Cipher | First Action |
|---|---|---|
| All uppercase letters, uneven frequency | Monoalphabetic substitution | Frequency analysis |
| All uppercase, flat frequency distribution | Polyalphabetic (Vigenere) | IC + Kasiski |
| Only A-Z shifted uniformly | Caesar/ROT | Brute force 25 shifts |
| Base64 alphabet (A-Za-z0-9+/=) | Base64 encoded (decode first) | Base64 decode |
| Hex string (0-9a-f) | Hex encoded (decode first) | Hex decode |
| Binary (0s and 1s) | Binary encoded | Convert to ASCII |
| Dots and dashes | Morse code | Morse decode |
| Raised/normal text pattern | Bacon cipher | Map to A/B, decode |
| 2-digit number pairs (11-55) | Polybius square | Grid lookup |
| Text appears scrambled (right letters, wrong order) | Transposition | Anagram analysis |
| Non-printable bytes XOR-like | XOR cipher | Single/repeating key XOR analysis |

---

## 1. CIPHER IDENTIFICATION METHODOLOGY

### 1.1 Step 1: Character Set Analysis

```python
def analyze_charset(ciphertext):
    """Identify encoding/cipher by character set."""
    chars = set(ciphertext.strip())

    if chars <= set('01 \n'):
        return "Binary encoding"
    if chars <= set('.-/ \n'):
        return "Morse code"
    if chars <= set('0123456789abcdef \n'):
        return "Hex encoding"
    if chars <= set('ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=\n'):
        if '=' in ciphertext or len(ciphertext) % 4 == 0:
            return "Base64 encoding"
    if chars <= set('ABCDEFGHIJKLMNOPQRSTUVWXYZ \n'):
        return "Uppercase only — classical cipher"
    if all(c in '12345' for c in ciphertext.replace(' ', '').replace('\n', '')):
        return "Polybius square (digits 1-5)"

    return "Mixed charset — needs further analysis"
```

### 1.2 Step 2: Frequency Analysis

```python
from collections import Counter

def frequency_analysis(text):
    """Compute letter frequency distribution."""
    text = text.upper()
    letters = [c for c in text if c.isalpha()]
    total = len(letters)
    freq = Counter(letters)

    print("Letter frequencies:")
    for letter, count in freq.most_common():
        pct = count / total * 100
        bar = '#' * int(pct)
        print(f"  {letter}: {pct:5.1f}% {bar}")

    return freq

# English letter frequency (for comparison):
# E T A O I N S H R D L C U M W F G Y P B V K J X Q Z
# 12.7 9.1 8.2 7.5 7.0 6.7 6.3 6.1 6.0 4.3 4.0 2.8 ...
```

### 1.3 Step 3: Index of Coincidence (IC)

```python
def index_of_coincidence(text):
    """
    IC ≈ 0.065 → English / monoalphabetic substitution
    IC ≈ 0.038 → random / polyalphabetic cipher
    """
    text = [c for c in text.upper() if c.isalpha()]
    N = len(text)
    freq = Counter(text)

    ic = sum(f * (f - 1) for f in freq.values()) / (N * (N - 1))
    return ic

# Interpretation:
# IC > 0.060 → monoalphabetic (Caesar, simple substitution, Playfair)
# IC ≈ 0.045-0.055 → polyalphabetic with short key (Vigenere key < 10)
# IC ≈ 0.038-0.042 → polyalphabetic with long key or random
```

### 1.4 Step 4: Kasiski Examination (for Polyalphabetic)

```python
from math import gcd
from functools import reduce

def kasiski(ciphertext, min_len=3):
    """Find repeated sequences and their distances → key length."""
    text = ''.join(c for c in ciphertext.upper() if c.isalpha())
    distances = []

    for length in range(min_len, min(20, len(text) // 3)):
        for i in range(len(text) - length):
            seq = text[i:i+length]
            j = text.find(seq, i + 1)
            while j != -1:
                distances.append(j - i)
                j = text.find(seq, j + 1)

    if not distances:
        return None

    # Key length is likely GCD of common distances
    common_gcds = Counter()
    for d in distances:
        for factor in range(2, min(d + 1, 30)):
            if d % factor == 0:
                common_gcds[factor] += 1

    print("Likely key lengths (by frequency):")
    for length, count in common_gcds.most_common(5):
        print(f"  Key length {length}: {count} occurrences")

    return common_gcds.most_common(1)[0][0]
```

---

## 2. MONOALPHABETIC SUBSTITUTION

### 2.1 Frequency Analysis Attack

```python
def solve_substitution(ciphertext, interactive=False):
    """Solve monoalphabetic substitution via frequency analysis."""
    freq = frequency_analysis(ciphertext)

    # English frequency order
    eng_order = "ETAOINSRHLDCUMWFGYPBVKJXQZ"
    cipher_order = ''.join(c for c, _ in freq.most_common())

    # Initial mapping (frequency-based guess)
    mapping = {}
    for i, c in enumerate(cipher_order):
        if i < len(eng_order):
            mapping[c] = eng_order[i]

    # Apply mapping
    result = ""
    for c in ciphertext.upper():
 

Excerpt, first 6,000 characters of SKILL.md, verbatim from the audited commit. It is text from someone else’s repository, quoted so you can judge it before your agent reads it.

Install

Pinned to the audited commit a6bc8e8

Download folder ↗
git clone https://github.com/yaklang/hack-skills
git -C hack-skills checkout a6bc8e8fefb6

The author documents no install command, so this uses the repository directly. Our verdict covers commit a6bc8e8fefb6 only.

Works in

The author has not said which agents this skill supports, and we have not tested it in any.

Audit history

Every audit, every source change

  1. ✓SAFE B 89 / 100

    first audit · source a6bc8e8fefb6

README badge

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Questions about classical-cipher-analysis

What does the classical-cipher-analysis skill do?
Helping AI Agent become an awesome practical hacker!
Is classical-cipher-analysis safe to install?
The audit found nothing in the source that contradicts what it says it does, and graded it B (89/100). Grade A is held back for packages that have also passed a sandboxed behavioural run, which is why a clean skill reads B.
What can classical-cipher-analysis access on my machine?
The audit observed no filesystem, network or shell use at all in its source.
How current is this page?
The grade is for one exact copy of the source (a6bc8e8fefb6), read on 2026-10-31. The repository is watched, and a new audit runs when it changes — this is the first audit.

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